CAN YOU PROVE LOGICALLY THE EXISTING 9 DIGITS WITHOUT THE GAP VALUES AT THE RIGHT SIDE AND CAN YOU DISPROVE LOGICALLY THESE 10 DIGITS WHICH ARE ONLY WITH THE GAP VALUES

CAN YOU PROVE LOGICALLY THE EXISTING 9 DIGITS WITHOUT THE GAP VALUES AT THE RIGHT SIDE
AND
CAN YOU DISPROVE LOGICALLY THESE 10 DIGITS WHICH ARE ONLY WITH THE GAP VALUES

Can you prove logically the 9 markings, from 1 to 9, alone are the existing 9 digits without considering the gap value at the right side of each marking also to be counted in the respective digit?

Against such present mathematical view on the existing 9 digits, without controversy we can prove logically that these 9 digits are to be counted only with the right-side gap value from each marking.

This diagram is the basement of the 10 digits,
whose capstone is nothing but the missing Digit 01.

Unlike the remaining 9 digits being with the mixed fractions, the newly proved Digit 01 alone is with the simple fractions of 1. Till the fullness of 1 there are two gap values, both at the left side from 0 to the marking of 1, and at the right side from the marking of 1 to the fullness of 1. So there are two 1^s till the fullness of 1 or two 1 values till the fullness of 1, each of which is lying at the left side with all the simple fractions of 1 as ¹⁄₄ → ¹⁄₂ → ³⁄₄ → 01 and lying at the right side with all the mixed fractions of 1 as 1¹⁄₄ → 1¹⁄₂ → 1³⁄₄ → fullness of 1.
So, 1 + 1 = 1 that is till the fullness of 1, and so 1 – 1 = 1 due to the two 1^s in the fullness of 1, as 1 × 1 = 1 and 1 ÷ 1 = 1.

Here the left-side 1 value is 01, while the right-side 1 value is Other 1.
But for all the remaining digits other than 01, there are only their respective mixed fractions at their right side.

For example, for Other 1, there are 1¹⁄₄ → 1¹⁄₂ → 1³⁄₄ → fullness of 1 for the starting of Digit 2 there , and again for Digit 2, there are 2¹⁄₄ → 2¹⁄₂ → 2³⁄₄ → fullness of 2 for the starting of Digit 3 there, and so on.

SO ‘01’ IS THE FIRST DIGIT BEING
FOUND NOW AS THE MISSING DIGIT

There are 10 digits when we count the gap values in this diagram (the basement diagram for the 10 digits), which are with their 10 gap values.

Here when there are 9 gap values with their respective mixed fractions at the right side of each marking, only one gap value alone is with the simple fractions of 1, only which alone is found with the strict 1 value that is in the first gap value between the valuable 0 and the marking of 1. Here when 0 is put at the left side of the marking of 1, surely it is the valuable 0 as the beginning point or the starting point.

Please mind that this found missing digit is not limited as 0 at the beginning being only as the starting point, but it is Digit 01 being with all the simple fractions in that first gap value totally possessed by 01. This newly found Digit 01 which represents the first gap value is the beginning digit, and so the base for the 10 digits.

This is while the Other 1 is found only in the second gap value, that also only with the mixed fractions of 1 between the marking of 1 and the fullness of 1.

This Other 1 which only represents the mixed fractions of 1 in the second gap value will never be the base and the beginning of the digits. But 01 which alone represents the simple fractions of 1 in the first gap value should be the base and the beginning of the digits. Thus now there are 10 digits with this New Digit 01, which has been the stolen digit missed by the Flat earth mathematicians of the bullockcart age even before Galileo (while the world was with the concept of the Flat earth). Till this generation of the present age of interplanetary journey, all the learners still ignorantly consider those bullockcart age mathematicians before the time of Galileo as the founders of Mathematics with their own view on 0 and 1, which all should be removed and altered.